-4+5m-4m^2=-m^2-m-10

Solution for -4+5m-4m^2=-m^2-m-10 equation:

-4+5m-4m^2=-m^2-m-10

We move all terms to the left:

-4+5m-4m^2-(-m^2-m-10)=0

We get rid of parentheses

-4m^2+m^2+m+5m+10-4=0

We add all the numbers together, and all the variables

-3m^2+6m+6=0

a = -3; b = 6; c = +6;
Δ = b2-4ac
Δ = 62-4·(-3)·6
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{3}}{2*-3}=\frac{-6-6\sqrt{3}}{-6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{3}}{2*-3}=\frac{-6+6\sqrt{3}}{-6}
$